integral from 0 to 3 of (3-x)^2

Lösung

\int_{0}^{3} (3 - x)^{2} d x

9

Schritte zur Lösung

\int_{0}^{3} (3 - x)^{2} d x

Multipliziere aus

(3 - x)^{2} : 9 - 6 x + x^{2}

= \int_{0}^{3} 9 - 6 x + x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 9 d x - \int_{0}^{3} 6 x d x + \int_{0}^{3} x^{2} d x

\int_{0}^{3} 9 d x = 27

\int_{0}^{3} 6 x d x = 27

\int_{0}^{3} x^{2} d x = 9

= 27 - 27 + 9

Vereinfache

= 9

y^{^{''}} + 5 y^{^{'}} + 4 y = 8 t e^{2 t}

x \to + 0 + lim (3 x)

d er i v a t i v e f (x) = x^{2} 4 x - 1

l a pl a ce t r an s f or m sin (5 t - \frac{π}{3}) \cdot 1 (5 t - \frac{π}{3})

in v erse l a pl a ce \frac{3 z - 5}{z ^{2} - 4 z + 3}