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Popular Calculus >

y^'=-0.5y

Solution

y^{^{'}} = - 0.5 y

Solution

y = e^{- 0.5 t + c_{1}}

Solution steps

y^{'} (t) = - 0.5 y

Solve separable ODE:

y = e^{- 0.5 t + c_{1}}

y = e^{- 0.5 t + c_{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-0.5y ?
The solution for y^'=-0.5y is y=e^{-0.5t+c_{1}}