What is (\partial)/(\partial y)((2x+3)(y-2)) ?

The answer to (\partial)/(\partial y)((2x+3)(y-2)) is 2x+3

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(\partial)/(\partial y)((2x+3)(y-2))

\frac{\partial}{\partial y} ((2 x + 3) (y - 2))

2 x + 3

Solution steps

\frac{\partial}{\partial y} ((2 x + 3) (y - 2))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (2 x + 3) \frac{\partial}{\partial y} (y - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (2 x + 3) (\frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (2))

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (2) = 0

= (2 x + 3) (1 - 0)

Simplify

= 2 x + 3

\frac{d}{d x} (2 e^{2 x} - e^{- x})

\frac{3}{4} x^{8}

y \to 0 lim (\frac{( 2 x )}{k y})

f (x) = \frac{x}{x + 2}

\frac{d}{d x} (12 e^{3 x})

What is (\partial)/(\partial y)((2x+3)(y-2)) ?
The answer to (\partial)/(\partial y)((2x+3)(y-2)) is 2x+3