What is the sum from n=0 to infinity of 2^{1/n} ?

The sum from n=0 to infinity of 2^{1/n} is diverges

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sum from n=0 to infinity of 2^{1/n}

n = 0 \sum \infty 2^{\frac{1}{n}}

diverges

Solution steps

n = 1 \sum \infty 2^{\frac{1}{n}}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=0 to infinity of 2^{1/n} ?
The sum from n=0 to infinity of 2^{1/n} is diverges