xy^'-y= 4/3 xln(x)

Lösung

x y^{^{'}} - y = \frac{4}{3} x ln (x)

y = \frac{2}{3} ln^{2} (x) x + c_{1} x

Schritte zur Lösung

x y^{'} (x) - y = \frac{4}{3} x ln (x)

Solve linear ODE:

y = \frac{2}{3} ln^{2} (x) x + c_{1} x

y = \frac{2}{3} ln^{2} (x) x + c_{1} x

\int \frac{x ^{2} - x + 36}{x ^{3} + 6 x} d x

\frac{\partial}{\partial x} (10 x (x^{2} + y^{2})^{\frac{1}{2}})

\frac{\partial}{\partial x} (\frac{x y}{1 + x})

\int - cos (d) x d x

n = 0 \sum \infty \frac{1}{2 n + 4}