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受欢迎的微积分 >

tangent f(x)=((x+1)/(x-3))^2,\at x=7

解答

切线

f (x) = (\frac{x + 1}{x - 3})^{2}, at x = 7

解答

y = - x + 11

求解步骤

找到切点:

(7, 4)

计算

f (x) = (\frac{x + 1}{x - 3})^{2}

的斜率:

\frac{df ( x )}{d x} = - \frac{8 ( x + 1 )}{( x - 3 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

找到斜率 m=

- 1

且穿过

(7, 4)

的直线:

y = - x + 11

y = - x + 11

作图

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