What is (\partial)/(\partial x)(y-1/(x^2)) ?

The answer to (\partial)/(\partial x)(y-1/(x^2)) is 2/(x^3)

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(\partial)/(\partial x)(y-1/(x^2))

\frac{\partial}{\partial x} (y - \frac{1}{x ^{2}})

\frac{2}{x ^{3}}

Solution steps

\frac{\partial}{\partial x} (y - \frac{1}{x ^{2}})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (\frac{1}{x ^{2}})

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= 0 - (- \frac{2}{x ^{3}})

Simplify

= \frac{2}{x ^{3}}

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What is (\partial)/(\partial x)(y-1/(x^2)) ?
The answer to (\partial)/(\partial x)(y-1/(x^2)) is 2/(x^3)