What is the tangent of f(x)=x^4+4x^2-x,(1,4) ?

The tangent of f(x)=x^4+4x^2-x,(1,4) is y=11x-7

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tangent of f(x)=x^4+4x^2-x,(1,4)

tangent of

f (x) = x^{4} + 4 x^{2} - x, (1, 4)

y = 11 x - 7

Solution steps

Find the slope of

f (x) = x^{4} + 4 x^{2} - x : \frac{df ( x )}{d x} = 4 x^{3} + 8 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 11

Find the line with slope m=

11

and passing through

(1, 4) : y = 11 x - 7

y = 11 x - 7

\int \frac{x ^{2}}{x ^{2} + 16} d x

n = 1 \sum \infty \frac{1000}{5 ^{n}}

5 + 4 e^{- 2 t}

\int (2 x) d x

\int x + y d x

What is the tangent of f(x)=x^4+4x^2-x,(1,4) ?
The tangent of f(x)=x^4+4x^2-x,(1,4) is y=11x-7