What is (\partial)/(\partial x)((-x)/(y^2)) ?

The answer to (\partial)/(\partial x)((-x)/(y^2)) is -1/(y^2)

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(\partial)/(\partial x)((-x)/(y^2))

\frac{\partial}{\partial x} (\frac{- x}{y ^{2}})

- \frac{1}{y ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{- x}{y ^{2}})

Simplify

\frac{- x}{y ^{2}} : - \frac{x}{y ^{2}}

= \frac{\partial}{\partial x} (- \frac{x}{y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{y ^{2}} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= - \frac{1}{y ^{2}} \cdot 1

Simplify

= - \frac{1}{y ^{2}}

\frac{d}{d x} (\frac{6}{x ^{7}})

h \to 1 lim (\frac{h ^{3} - 1}{h - 1})

x \to 3 lim (- 3 x^{3} + 9 x + 5 x - 5)

x y^{^{'}} + 2 y = sin (x)

\frac{\partial}{\partial y} (8 y - 4 x)

What is (\partial)/(\partial x)((-x)/(y^2)) ?
The answer to (\partial)/(\partial x)((-x)/(y^2)) is -1/(y^2)