fläche y=5x^2,y^2= 1/5 x

Lösung

fläche

y = 5 x^{2}, y^{2} = \frac{1}{5} x

\frac{1}{75}

Dezimale

0.01333 \dots

Schritte zur Lösung

Stelle

y

nach

y^{2} = \frac{1}{5} x

um:

y = \frac{x}{5}, y = - \frac{x}{5}

f_{1} (x) = 5 x^{2}

f_{2} (x) = \frac{x}{5}

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

5 x^{2} = \frac{x}{5} : x = 0, x = \frac{1}{5}

5 x^{2} = - \frac{x}{5} : x = 0

\frac{x}{5} = - \frac{x}{5} : x = 0

= \int_{0}^{\frac{1}{5}} ∣ f_{1} (x) - f_{2} (x) ∣ d x

= \int_{0}^{\frac{1}{5}} 5 x^{2} - \frac{x}{5} d x

\int_{0}^{\frac{1}{5}} 5 x^{2} - \frac{x}{5} d x = \frac{1}{75}

= \frac{1}{75}

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