derivative of x^3+2x^2-1

Lösung

\frac{d}{d x} (x^{3} + 2 x^{2} - 1)

3 x^{2} + 4 x

Schritte zur Lösung

\frac{d}{d x} (x^{3} + 2 x^{2} - 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 3 x^{2} + 4 x - 0

Vereinfache

= 3 x^{2} + 4 x

\int x (1 - x)^{99} d x

\int \frac{x}{x ^{4} + 4 x ^{2} + 5} d x

x \to 2 + lim (\frac{2 - x}{∣ x - 2 ∣})

t \to 0 lim (\frac{e ^{\frac{1}{t}}}{t})

im pl i c i t \frac{d y}{d x}, 2 x^{3} - 5 x y - y^{2} = 3