integral of-2x^2+4x

Lösung

\int - 2 x^{2} + 4 x d x

- \frac{2 x ^{3}}{3} + 2 x^{2} + C

Schritte zur Lösung

\int - 2 x^{2} + 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2 x^{2} d x + \int 4 x d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 4 x d x = 2 x^{2}

= - \frac{2 x ^{3}}{3} + 2 x^{2}

Füge eine Konstante zur Lösung hinzu

= - \frac{2 x ^{3}}{3} + 2 x^{2} + C

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