(\partial)/(\partial x)(9xy+sin(y))

解答

\frac{\partial}{\partial x} (9 x y + sin (y))

9 y

求解步骤

\frac{\partial}{\partial x} (9 x y + sin (y))

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 x y) + \frac{\partial}{\partial x} (sin (y))

\frac{\partial}{\partial x} (9 x y) = 9 y

\frac{\partial}{\partial x} (sin (y)) = 0

= 9 y + 0

化简

= 9 y

\frac{\partial}{\partial x} (\frac{5 x + 8}{4 y + 1})

d er i v a t i v e f (x) = (4 x)

\frac{\partial}{\partial x} (e^{3 5 x})

\int_{0}^{2 π} sin^{2} (6 x) d x

x \to 3 lim (lo g_{3} (x))