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Beliebt Rechnen >

y^'-y=10te^{2t},y(0)=1

Lösung

y^{^{'}} - y = 10 t e^{2 t}, y (0) = 1

Lösung

y = 10 e^{2 t} (t - 1) + 11 e^{t}

Schritte zur Lösung

y^{'} (t) - y = 10 t e^{2 t}

Solve linear ODE:

y = 10 e^{2 t} (t - 1) + 11 e^{t}

y = 10 e^{2 t} (t - 1) + 11 e^{t}

Graph

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