csc(y)dx+sec(2x)dy=0

Lösung

csc (y) d x + sec (2 x) d y = 0

y = arccos (- \frac{- sin ( 2 x ) + c _{1}}{2}) + 2 πn, y = - arccos (- \frac{- sin ( 2 x ) + c _{1}}{2}) + 2 πn

Schritte zur Lösung

csc (y) d x + sec (2 x) d y = 0

Solve separable ODE:

y = arccos (- \frac{- sin ( 2 x ) + c _{1}}{2}) + 2 πn, y = - arccos (- \frac{- sin ( 2 x ) + c _{1}}{2}) + 2 πn

y = arccos (- \frac{- sin ( 2 x ) + c _{1}}{2}) + 2 πn, y = - arccos (- \frac{- sin ( 2 x ) + c _{1}}{2}) + 2 πn

\frac{\partial}{\partial x} (cos (π) x)

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{1 + 2 x})

\int_{\frac{1}{2}}^{2} (1 - \frac{1}{x ^{2}}) d x

\frac{d y}{d x} = y + x^{2}

\int_{3}^{\infty} \frac{1}{x ^{2}} d x