(\partial)/(\partial y)(-1/2 x-3y+1)

解

\frac{\partial}{\partial y} (- \frac{1}{2} x - 3 y + 1)

- 3

解答ステップ

\frac{\partial}{\partial y} (- \frac{1}{2} x - 3 y + 1)

簡素化

- \frac{1}{2} x - 3 y + 1 : - \frac{x}{2} - 3 y + 1

= \frac{\partial}{\partial y} (- \frac{x}{2} - 3 y + 1)

x

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial y} (\frac{x}{2}) - \frac{\partial}{\partial y} (3 y) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (\frac{x}{2}) = 0

\frac{\partial}{\partial y} (3 y) = 3

\frac{\partial}{\partial y} (1) = 0

= - 0 - 3 + 0

簡素化

= - 3