derivative of 8/(3x^2+3/(2x)+2)

Lösung

\frac{d}{d x} (\frac{8}{3 x ^{2}} + \frac{3}{2 x} + 2)

- \frac{16}{3 x ^{3}} - \frac{3}{2 x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{8}{3 x ^{2}} + \frac{3}{2 x} + 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{8}{3 x ^{2}}) + \frac{d}{d x} (\frac{3}{2 x}) + \frac{d}{d x} (2)

\frac{d}{d x} (\frac{8}{3 x ^{2}}) = - \frac{16}{3 x ^{3}}

\frac{d}{d x} (\frac{3}{2 x}) = - \frac{3}{2 x ^{2}}

\frac{d}{d x} (2) = 0

= - \frac{16}{3 x ^{3}} - \frac{3}{2 x ^{2}} + 0

Vereinfache

= - \frac{16}{3 x ^{3}} - \frac{3}{2 x ^{2}}

d er i v a t i v e 3 x + 7

f^{^{'}} (x) = x^{4} (x - 2) (x + 3)

\int 10 x + 11 d x

\int x^{2} 8 x^{3} + 1 d x

\frac{d}{d x} (2 sec (x) - 7 x)