(\partial}{\partial y}(\frac{(2x+y))/z)

Lösung

\frac{\partial}{\partial y} (\frac{( 2 x + y )}{z})

\frac{1}{z}

Schritte zur Lösung

\frac{\partial}{\partial y} (\frac{( 2 x + y )}{z})

Behandle

x, z

als Konstanten

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial y} (2 x + y)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial y} (2 x) + \frac{\partial}{\partial y} (y))

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (y) = 1

= \frac{1}{z} (0 + 1)

Vereinfache

= \frac{1}{z}

t an g e n t f (x) = \frac{4}{x}, (4, 2)

d er i v a t i v e 4 e^{4 x}

d er i v a t i v e 6 x + 5

\int_{0}^{\frac{π}{6}} cos (9 x) d x

\int \frac{cos ( \frac{π}{x ^{11}} )}{x ^{12}} d x