面积 y=sqrt(x),y=x^2,y=1

解答

面积

y = x, y = x^{2}, y = 1

无解

求解步骤

要找到相交点，解

f_{i} (x) = f_{j} (x)

x = x^{2} : x = 0, x = 1

x = 1 : x = 1

x^{2} = 1 : x = 1, x = - 1

曲线没有界限

= 无解

\int \frac{cos ( \frac{π}{x ^{3}} )}{x ^{4}} d x

d er i v a t i v e lo g_{4} (sec^{2} (5 x^{3} - 4 x^{2}))

\int_{0}^{30} 500 d x

(y^{3} - 1) e^{x} d x + 3 y^{2} (e^{x} + 1) d y = 0, y (0) = 2

t an g e n t f (x) = 2 (3 x - 8)^{4} - 5 x + 6, at x = 3