limit as x approaches infinity of (3x-2)/(6x+1)

解

x \to \infty lim (\frac{3 x - 2}{6 x + 1})

\frac{1}{2}

十進法表記

0.5

解答ステップ

x \to \infty lim (\frac{3 x - 2}{6 x + 1})

最高の分母べき乗で割る:

\frac{3 - \frac{2}{x}}{6 + \frac{1}{x}}

= x \to \infty lim (\frac{3 - \frac{2}{x}}{6 + \frac{1}{x}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

不定形式の場合を除く

= \frac{lim _{x \to \infty} ( 3 - \frac{2}{x} )}{lim _{x \to \infty} ( 6 + \frac{1}{x} )}

x \to \infty lim (3 - \frac{2}{x}) = 3

x \to \infty lim (6 + \frac{1}{x}) = 6

= \frac{3}{6}

共通因数を約分する:

3

= \frac{1}{2}