What is the derivative of f(x)=(sec(x))/x ?

The derivative of f(x)=(sec(x))/x is (-1+xtan(x))/(x^2cos(x))

What is the first derivative of f(x)=(sec(x))/x ?

The first derivative of f(x)=(sec(x))/x is (-1+xtan(x))/(x^2cos(x))

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derivative of

f (x) = \frac{sec ( x )}{x}

\frac{- 1 + x tan ( x )}{x ^{2} cos ( x )}

Solution steps

\frac{d}{d x} (\frac{sec ( x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( sec ( x ) ) x - \frac{d x}{d x} sec ( x )}{x ^{2}}

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d x}{d x} = 1

= \frac{sec ( x ) tan ( x ) x - 1 \cdot sec ( x )}{x ^{2}}

Simplify

\frac{sec ( x ) tan ( x ) x - 1 \cdot sec ( x )}{x ^{2}} : \frac{- 1 + x tan ( x )}{x ^{2} cos ( x )}

= \frac{- 1 + x tan ( x )}{x ^{2} cos ( x )}

\frac{\partial}{\partial x} (6 x y^{5} + 4 y^{3})

\frac{d}{d x} (- x^{π})

\int \frac{x + 3}{1 - x ^{2}} d x

\frac{\partial}{\partial x} ((3 x + 2 y) e^{\frac{x}{y}})

x \to 1 lim (sin^{2} (x - 1))

What is the derivative of f(x)=(sec(x))/x ?
The derivative of f(x)=(sec(x))/x is (-1+xtan(x))/(x^2cos(x))
What is the first derivative of f(x)=(sec(x))/x ?
The first derivative of f(x)=(sec(x))/x is (-1+xtan(x))/(x^2cos(x))