y^'+y=x+sqrt(5)

Lösung

y^{^{'}} + y = x + 5

y = x - 1 + 5 + \frac{c _{1}}{e ^{x}}

Schritte zur Lösung

y^{'} (x) + y = x + 5

Solve linear ODE:

y = x - 1 + 5 + \frac{c _{1}}{e ^{x}}

y = x - 1 + 5 + \frac{c _{1}}{e ^{x}}

\int \frac{1}{64 + x ^{2}} d x

\int \frac{( x ^{3} )}{1 + x ^{2}} d x

d er i v a t i v e 2 x^{2} + x - 2

\int_{0}^{\infty} \frac{5}{x ^{3}} d x

t an g e n t 0 = x^{2} - x y + 2 y - 2, at x = - 2