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Beliebt Rechnen >

y^'+2x^2=0

Lösung

y^{^{'}} + 2 x^{2} = 0

Lösung

y = - \frac{2 x ^{3}}{3} + c_{1}

Schritte zur Lösung

y^{'} (x) + 2 x^{2} = 0

Isoliere

y^{'} (x) : y^{'} (x) = - 2 x^{2}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int - 2 x^{2} d x

\int - 2 x^{2} d x = - \frac{2 x ^{3}}{3} + c_{1}

y = - \frac{2 x ^{3}}{3} + c_{1}

Graph

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