What is the derivative of (3x+6^2) ?

The derivative of (3x+6^2) is 6(3x+6)

What is the first derivative of (3x+6^2) ?

The first derivative of (3x+6^2) is 6(3x+6)

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\frac{d}{d x} ((3 x + 6)^{2})

6 (3 x + 6)

Solution steps

\frac{d}{d x} ((3 x + 6)^{2})

Apply the chain rule:

2 (3 x + 6) \frac{d}{d x} (3 x + 6)

= 2 (3 x + 6) \frac{d}{d x} (3 x + 6)

\frac{d}{d x} (3 x + 6) = 3

= 2 (3 x + 6) \cdot 3

Simplify

= 6 (3 x + 6)

a re a y = - x^{2} - 2 x + 3, y = - x + 1

\int \frac{( x - 1 )}{( x ^{2} - 2 x - 35 ) ^{7}} d x

d er i v a t i v e \frac{9}{t}

d er i v a t i v e y = \frac{e ^{4 x^{2 + 1}}}{8}

\frac{\partial}{\partial y} (x^{2} y^{4} + z^{3})

What is the derivative of (3x+6^2) ?
The derivative of (3x+6^2) is 6(3x+6)
What is the first derivative of (3x+6^2) ?
The first derivative of (3x+6^2) is 6(3x+6)