What is the derivative of x^3+1 ?

The derivative of x^3+1 is 3x^2

What is the first derivative of x^3+1 ?

The first derivative of x^3+1 is 3x^2

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derivative of

x^{3} + 1

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (1) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

x \to - \infty lim (3 x + 9 x^{2} + 7 x - 8)

\int 16 x d x

\int \frac{40 x}{5 x ^{2} + e} d x

x \to 0 + lim (tan (x) ln (x))

\frac{d}{d x} (3 x + x)