integral of (x^2+24x-9)/(x^3-9x)

Lösung

\int \frac{x ^{2} + 24 x - 9}{x ^{3} - 9 x} d x

ln ∣ x ∣ - 4 ln ∣ x + 3 ∣ + 4 ln ∣ x - 3 ∣ + C

Schritte zur Lösung

\int \frac{x ^{2} + 24 x - 9}{x ^{3} - 9 x} d x

Ermittle den Partialbruch von

\frac{x ^{2} + 24 x - 9}{x ^{3} - 9 x} : \frac{1}{x} - \frac{4}{x + 3} + \frac{4}{x - 3}

= \int \frac{1}{x} - \frac{4}{x + 3} + \frac{4}{x - 3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x - \int \frac{4}{x + 3} d x + \int \frac{4}{x - 3} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{4}{x + 3} d x = 4 ln ∣ x + 3 ∣

\int \frac{4}{x - 3} d x = 4 ln ∣ x - 3 ∣

= ln ∣ x ∣ - 4 ln ∣ x + 3 ∣ + 4 ln ∣ x - 3 ∣

Füge eine Konstante zur Lösung hinzu

= ln ∣ x ∣ - 4 ln ∣ x + 3 ∣ + 4 ln ∣ x - 3 ∣ + C

x \to \frac{π}{2} lim (- cos (x))

d er i v a t i v e y = \frac{6 x ^{2} + 6 x + 2}{x}

d er i v a t i v e 5 cos (x)

\frac{\partial}{\partial x} (x ln (t))

d er i v a t i v e e^{x} - e^{- x}