derivative of tan(2x^5)

Lösung

\frac{d}{d x} (tan (2 x^{5}))

sec^{2} (2 x^{5}) \cdot 10 x^{4}

Schritte zur Lösung

\frac{d}{d x} (tan (2 x^{5}))

Wende die Kettenregel an:

sec^{2} (2 x^{5}) \frac{d}{d x} (2 x^{5})

= sec^{2} (2 x^{5}) \frac{d}{d x} (2 x^{5})

\frac{d}{d x} (2 x^{5}) = 10 x^{4}

= sec^{2} (2 x^{5}) \cdot 10 x^{4}

\int \frac{2 x}{x ^{2} - x - 2} d x

s \to 0 lim (\frac{1}{s ^{2} 0.1 s + 1})

x \to 0 lim (\frac{sin ^{2} ( 6 x )}{x})

x \to \infty lim (2 x^{x})

y^{^{''}} + 3 y^{^{'}} = 0, y (0) = 9, y^{^{'}} (0) = - 6