taylor e^{3x}

Lösung

taylor

e^{3 x}

1 + 3 x + \frac{9}{2} x^{2} + \frac{9}{2} x^{3} + \frac{27}{8} x^{4} + \dots

Schritte zur Lösung

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( e ^{3 x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{3 x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{3 x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{3}{1 !} x + \frac{9}{2 !} x^{2} + \frac{27}{3 !} x^{3} + \frac{81}{4 !} x^{4} + \dots

Fasse zusammen

= 1 + 3 x + \frac{9}{2} x^{2} + \frac{9}{2} x^{3} + \frac{27}{8} x^{4} + \dots

x (\frac{d y}{d x}) = 4 y

l a pl a ce t r an s f or m {6 e^{- 3 t} - t^{2} + 2 t - 8}

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\int_{1}^{7} (6 x^{2} + 2 x - 3) d x