y^'=(x+y)^2-1,y(1)=6

Lösung

y^{^{'}} = (x + y)^{2} - 1, y (1) = 6

y = - \frac{7}{7 x - 8} - x

Schritte zur Lösung

y^{'} (x) = (x + y)^{2} - 1

Solve using substitution:

y = - \frac{7}{7 x - 8} - x

y = - \frac{7}{7 x - 8} - x

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