What is the solution for (dy)/(dx)=(x+y)^2 ?

The solution for (dy)/(dx)=(x+y)^2 is y=tan(x+c_{1})-x

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(dy)/(dx)=(x+y)^2

\frac{d y}{d x} = (x + y)^{2}

y = tan (x + c_{1}) - x

Solution steps

\frac{d y}{d x} = (x + y)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x

y = tan (x + c_{1}) - x

f (x) = \frac{1}{2 x}, at x = 9

f (x) = (x^{4} - \frac{5}{x ^{3}})^{- 4}

\int_{0}^{3} \frac{x}{x + 1} d x

n = 1 \sum \infty \frac{2 n}{3 n - 2}

\frac{d y}{d x} = (y - 1) x

What is the solution for (dy)/(dx)=(x+y)^2 ?
The solution for (dy)/(dx)=(x+y)^2 is y=tan(x+c_{1})-x