taylor f(x)=3x^2-6x+5

Lösung

taylor

f (x) = 3 x^{2} - 6 x + 5

5 - 6 x + 3 x^{2}

Schritte zur Lösung

Apply the Taylor Formula

= 5 + \frac{\frac{d}{d x} ( 3 x ^{2} - 6 x + 5 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 3 x ^{2} - 6 x + 5 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 3 x ^{2} - 6 x + 5 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 5 + \frac{- 6}{1 !} x + \frac{6}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Fasse zusammen

= 5 - 6 x + 3 x^{2}

\int_{0}^{\frac{π}{2}} 7 sin^{2} (2 x) d x

\int e^{7 x} (7) d x

a re a x + y = 7, x + 5 = y^{2}

a re a x = y^{2} + 2, x = 6

\frac{d}{d x} (- 4.5 x e^{- \frac{x}{3.8}})