(\partial)/(\partial x)(3x^2+ycos(xy))

Lösung

\frac{\partial}{\partial x} (3 x^{2} + y cos (x y))

6 x - y^{2} sin (y x)

Schritte zur Lösung

\frac{\partial}{\partial x} (3 x^{2} + y cos (x y))

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (y cos (x y))

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (y cos (x y)) = - y^{2} sin (y x)

= 6 x - y^{2} sin (y x)

\frac{\partial}{\partial x} (sin (2 x) cos (8 y))

\frac{d ^{2}}{d x ^{2}} (x^{2} + 21)

\int_{0}^{3} (2 x - x^{2})^{4} (1 - x) d x

\frac{\partial}{\partial x} (2 x y - 18 x)

d er i v a t i v e \frac{3 x}{x ^{2} + 1}