derivative of sqrt((1-cx/(1+cx)))

Lösung

\frac{d}{d x} (\frac{1 - c x}{1 + c x})

\frac{1}{2 \frac{1 - c x}{1 + c x}} \cdot \frac{( - c ) ( 1 + c x ) - c ( 1 - c x )}{( 1 + c x ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{1 - c x}{1 + c x})

Wende die Kettenregel an:

\frac{1}{2 \frac{1 - c x}{1 + c x}} \frac{d}{d x} (\frac{1 - c x}{1 + c x})

= \frac{1}{2 \frac{1 - c x}{1 + c x}} \frac{d}{d x} (\frac{1 - c x}{1 + c x})

\frac{d}{d x} (\frac{1 - c x}{1 + c x}) = \frac{( - c ) ( 1 + c x ) - c ( 1 - c x )}{( 1 + c x ) ^{2}}

= \frac{1}{2 \frac{1 - c x}{1 + c x}} \cdot \frac{( - c ) ( 1 + c x ) - c ( 1 - c x )}{( 1 + c x ) ^{2}}

\int \frac{x ^{3}}{2 - x ^{2}} d x

\frac{d y}{d x} = \frac{1}{3} x^{3}

d er i v a t i v e 13

\int sec^{2} (x) ln (tan (x)) d x

\int 2 tan (4 x) d x