What is the derivative of 3cos(2u) ?

The derivative of 3cos(2u) is -6sin(2u)

What is the first derivative of 3cos(2u) ?

The first derivative of 3cos(2u) is -6sin(2u)

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derivative of

3 cos (2 u)

- 6 sin (2 u)

Solution steps

\frac{d}{d u} (3 cos (2 u))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d u} (cos (2 u))

Apply the chain rule:

- sin (2 u) \frac{d}{d u} (2 u)

= - sin (2 u) \frac{d}{d u} (2 u)

\frac{d}{d u} (2 u) = 2

= 3 (- sin (2 u) \cdot 2)

Simplify

= - 6 sin (2 u)

n = 2 \sum \infty \frac{1}{n ^{2} + n}

\frac{1}{s ^{2} - 3}

\frac{d}{d x} (- 3 e^{1 - 3 x})

\frac{d}{d x} (2 x + 4)

\frac{\partial}{\partial x} (\frac{( - y )}{x ^{2} + y ^{2}})

What is the derivative of 3cos(2u) ?
The derivative of 3cos(2u) is -6sin(2u)
What is the first derivative of 3cos(2u) ?
The first derivative of 3cos(2u) is -6sin(2u)