y^'=4y^2x

Lösung

y^{^{'}} = 4 y^{2} x

y = - \frac{1}{2 x ^{2} + c _{1}}

Schritte zur Lösung

y^{'} (x) = 4 y^{2} x

Solve separable ODE:

y = - \frac{1}{2 x ^{2} + c _{1}}

y = - \frac{1}{2 x ^{2} + c _{1}}

\int 13 tan^{5} (x) d x

\int \frac{t ^{2}}{1 + t ^{3}} d t

\int \frac{2 x}{1 + 3 x} d x

im pl i c i t \frac{d y}{d x}, x^{4} y - 8 x y + 3 x y^{2} = 9

x \to 0 lim (\frac{cos ( 3 x - \frac{π}{2} )}{x})