(2x-1)dx+(5y+6)dy=0

Lösung

(2 x - 1) d x + (5 y + 6) d y = 0

y = \frac{- 12 + 144 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 12 - 144 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

Schritte zur Lösung

(2 x - 1) d x + (5 y + 6) d y = 0

Solve separable ODE:

y = \frac{- 12 + 144 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 12 - 144 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

y = \frac{- 12 + 144 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 12 - 144 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

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\frac{d ^{3}}{d x ^{3}} (2 x)

\int_{1}^{3} 9 arctan (1 x) d x