implicit (dy)/(dx),xe^y-10x+3y=0

解答

隐函数求导

\frac{d y}{d x}, x e^{y} - 10 x + 3 y = 0

\frac{d y}{d x} = \frac{- e ^{y} + 10}{e ^{y} x + 3}

求解步骤

x e^{y} - 10 x + 3 y = 0

将

y

视为

y (x)

对两侧微分:

e^{y} + e^{y} x \frac{d y}{d x} - 10 + 3 \frac{d y}{d x} = 0

整理

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- e ^{y} + 10}{e ^{y} x + 3}

\frac{d y}{d x} = \frac{- e ^{y} + 10}{e ^{y} x + 3}

d er i v a t i v e (sin (3 x))^{l n (x)}

\frac{\partial}{\partial x} (2 x + y^{2})

\frac{d}{d x} (arcsinh (tan (x)))

\frac{d}{d x} (\frac{1 - 2 x}{4 + x})

n = 0 \sum \infty 4 (\frac{2}{3})^{2 n}