limit as n approaches infinity of (2n^5-3n^4+8)/(3n^5+1)

解

n \to \infty lim (\frac{2 n ^{5} - 3 n ^{4} + 8}{3 n ^{5} + 1})

\frac{2}{3}

十進法表記

0.66666 \dots

解答ステップ

n \to \infty lim (\frac{2 n ^{5} - 3 n ^{4} + 8}{3 n ^{5} + 1})

最高の分母べき乗で割る:

\frac{2 - \frac{3}{n} + \frac{8}{n ^{5}}}{3 + \frac{1}{n ^{5}}}

= n \to \infty lim (\frac{2 - \frac{3}{n} + \frac{8}{n ^{5}}}{3 + \frac{1}{n ^{5}}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

不定形式の場合を除く

= \frac{lim _{n \to \infty} ( 2 - \frac{3}{n} + \frac{8}{n ^{5}} )}{lim _{n \to \infty} ( 3 + \frac{1}{n ^{5}} )}

n \to \infty lim (2 - \frac{3}{n} + \frac{8}{n ^{5}}) = 2

n \to \infty lim (3 + \frac{1}{n ^{5}}) = 3

= \frac{2}{3}