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受欢迎的微积分 >

tangent sqrt(sin(7x))

解答

切线

sin (7 x)

解答

y = \frac{7 cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )} x + sin (7 a_{0}) - \frac{7 a _{0} cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, sin (7 a_{0}))

计算

y = sin (7 x)

的斜率:

\frac{d y}{d x} = \frac{7 cos ( 7 x )}{2 sin ( 7 x )}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7 cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )}

找到斜率 m=

\frac{7 cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )}

且穿过

(a_{0}, sin (7 a_{0}))

的直线:

y = \frac{7 cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )} x + sin (7 a_{0}) - \frac{7 a _{0} cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )}

y = \frac{7 cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )} x + sin (7 a_{0}) - \frac{7 a _{0} cos ( 7 a _{0} )}{2 sin ( 7 a _{0} )}

作图

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