integral of (3x+2)cos(5x)

Lösung

\int (3 x + 2) cos (5 x) d x

\frac{3}{25} (5 x sin (5 x) + cos (5 x)) + \frac{2}{5} sin (5 x) + C

Schritte zur Lösung

\int (3 x + 2) cos (5 x) d x

Multipliziere aus

(3 x + 2) cos (5 x) : 3 x cos (5 x) + 2 cos (5 x)

= \int 3 x cos (5 x) + 2 cos (5 x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x cos (5 x) d x + \int 2 cos (5 x) d x

\int 3 x cos (5 x) d x = \frac{3}{25} (5 x sin (5 x) + cos (5 x))

\int 2 cos (5 x) d x = \frac{2}{5} sin (5 x)

= \frac{3}{25} (5 x sin (5 x) + cos (5 x)) + \frac{2}{5} sin (5 x)

Füge eine Konstante zur Lösung hinzu

= \frac{3}{25} (5 x sin (5 x) + cos (5 x)) + \frac{2}{5} sin (5 x) + C

a re a y = x (x + 2) (x - 2), [- 2, 1]

\int_{1}^{4} - 6 t ln (t) d t

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