integral of x^3-2x+3

Lösung

\int x^{3} - 2 x + 3 d x

\frac{x ^{4}}{4} - x^{2} + 3 x + C

Schritte zur Lösung

\int x^{3} - 2 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 2 x d x + \int 3 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 2 x d x = x^{2}

\int 3 d x = 3 x

= \frac{x ^{4}}{4} - x^{2} + 3 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{4}}{4} - x^{2} + 3 x + C

\frac{\partial}{\partial x} (9 x)

x \to 4 lim (x^{3})

x \to - 2 lim (\frac{( 3 )}{x + 2})

\int (x^{2} - \frac{15}{2} x + x^{- \frac{4}{3}}) d x

\int \frac{x}{2 - 3 x} d x