derivative mx+b

解答

导数

m x + b

m

求解步骤

\frac{d}{d x} (m x + b)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (m x) + \frac{d b}{d x}

\frac{d}{d x} (m x) = m

\frac{d b}{d x} = 0

= m + 0

化简

= m

\frac{\partial}{\partial x} (- k p (x) gx + A)

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