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Beliebt Rechnen >

2y^'+y=8t^2

Lösung

2 y^{^{'}} + y = 8 t^{2}

Lösung

y = 8 (t^{2} - 8 (\frac{1}{2} t - 1)) + \frac{c _{1}}{e ^{\frac{t}{2}}}

Schritte zur Lösung

2 y^{'} (t) + y = 8 t^{2}

Solve linear ODE:

y = 8 (t^{2} - 8 (\frac{1}{2} t - 1)) + \frac{c _{1}}{e ^{\frac{t}{2}}}

y = 8 (t^{2} - 8 (\frac{1}{2} t - 1)) + \frac{c _{1}}{e ^{\frac{t}{2}}}

Graph

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