x^'=(x-4)^2

Lösung

x^{^{'}} = (x - 4)^{2}

x = - \frac{1}{t + c _{1}} + \frac{4 t}{t + c _{1}} + \frac{4 c _{1}}{t + c _{1}}

Schritte zur Lösung

x^{'} (t) = (x - 4)^{2}

Solve separable ODE:

x = - \frac{1}{t + c _{1}} + \frac{4 t}{t + c _{1}} + \frac{4 c _{1}}{t + c _{1}}

x = - \frac{1}{t + c _{1}} + \frac{4 t}{t + c _{1}} + \frac{4 c _{1}}{t + c _{1}}

d er i v a t i v e \frac{( e ^{2 p} + 1 )}{3 e ^{2 p}}

x \to 7 + lim (- 2 x^{2} + 2)

d er i v a t i v e sin (9 x) + sin^{2} (9 x)

\int (4 x + 5)^{2} d x

x \to \frac{1}{3} lim ((9 x - 3)^{3})