(13+x^2)y^'-2xy=0

Lösung

(13 + x^{2}) y^{^{'}} - 2 x y = 0

y = 13 e^{c_{1}} + e^{c_{1}} x^{2}

Schritte zur Lösung

(13 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 13 e^{c_{1}} + e^{c_{1}} x^{2}

y = 13 e^{c_{1}} + e^{c_{1}} x^{2}

\frac{\partial}{\partial x} (y x + 2 x + g (y))

y^{^{'}} = - x y

t an g e n t f (x) = x^{3} - 2 x + 2, at x = 3

\frac{\partial}{\partial x} (ln (a x + b y) + c^{x + y})

\int \frac{cos ( x )}{sin ^{2} ( x )} d x