derivative of a^2x^2+bx+49

Lösung

\frac{d}{d x} (a^{2} x^{2} + b x + 49)

2 a^{2} x + b

Schritte zur Lösung

\frac{d}{d x} (a^{2} x^{2} + b x + 49)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{2} x^{2}) + \frac{d}{d x} (b x) + \frac{d}{d x} (49)

\frac{d}{d x} (a^{2} x^{2}) = 2 a^{2} x

\frac{d}{d x} (b x) = b

\frac{d}{d x} (49) = 0

= 2 a^{2} x + b + 0

Vereinfache

= 2 a^{2} x + b

\int (x^{2} + x + 1) \cdot sin (x) d x

\int \frac{arctan ( 4 x )}{1 + 16 x ^{2}} d x

t an g e n t y = 5 x - 2 x^{2}, (- 3, - 33)

\int 1 + 2 cos (2 θ) + \frac{1}{2} (1 + cos (4 θ)) d θ

(12 x^{2} + y - 1) d x - (10 y - x) d y = 0, y (1) = 0