derivative of ln((x+1^2))

Lösung

\frac{d}{d x} (ln ((x + 1)^{2}))

\frac{2}{x + 1}

Schritte zur Lösung

\frac{d}{d x} (ln ((x + 1)^{2}))

Wende die Kettenregel an:

\frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} ((x + 1)^{2})

= \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} ((x + 1)^{2})

\frac{d}{d x} ((x + 1)^{2}) = 2 (x + 1)

= \frac{1}{( x + 1 ) ^{2}} \cdot 2 (x + 1)

Vereinfache

\frac{1}{( x + 1 ) ^{2}} \cdot 2 (x + 1) : \frac{2}{x + 1}

= \frac{2}{x + 1}

\frac{\partial}{\partial x} (\frac{1}{x - a})

\int sin (x) sec^{2} (x) d x

\frac{\partial}{\partial x} (4 x^{3} + 4 x y^{2})

l a pl a ce t r an s f or m e^{- 3 t}

(t^{2} + 16) (\frac{d x}{d t}) = (x^{2} + 25), x (0) = 5