cos^2(t)y^'=1

Lösung

cos^{2} (t) y^{^{'}} = 1

y = tan (t) + c_{1}

Schritte zur Lösung

cos^{2} (t) y^{'} (t) = 1

Isoliere

y^{'} (t) : y^{'} (t) = \frac{1}{cos ^{2} ( t )}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{1}{cos ^{2} ( t )} d t

\int \frac{1}{cos ^{2} ( t )} d t = tan (t) + c_{1}

y = tan (t) + c_{1}

\int \frac{1}{e ^{y}} d y

\frac{d y}{d x} + \frac{2 x}{1 + x ^{2}} y = - 2 x y^{2}

\int_{1}^{x} 2 (x - 1) d x

d er i v a t i v e f (x) = arctan (x^{10})

l a pl a ce t r an s f or m 3 t^{4} + 7 t^{2} - 5