y^'=-3y^2

Lösung

y^{^{'}} = - 3 y^{2}

y = - \frac{1}{- 3 t + c _{1}}

Schritte zur Lösung

y^{'} (t) = - 3 y^{2}

Solve separable ODE:

y = - \frac{1}{- 3 t + c _{1}}

y = - \frac{1}{- 3 t + c _{1}}

\frac{d}{d x} (\frac{1}{12} (x + 3)^{3} + (x + 3)^{- 1})

\int_{1}^{4} t ln (\frac{t}{2}) d t

\int \frac{4 x}{1 - 16 x ^{4}} d x

n or ma l y = \frac{x}{a} + \frac{a}{x}, at x = \frac{a}{2}

x \to 5 lim ([x])