integral from 0 to 5 of x^3

解答

\int_{0}^{5} x^{3} d x

\frac{625}{4}

十进制

156.25

求解步骤

\int_{0}^{5} x^{3} d x

使用幂法则

= [\frac{x ^{4}}{4}]_{0}^{5}

带入上下限计算后得:

\frac{625}{4}

= \frac{625}{4}

y^{^{''}} x^{2} - 5 x y^{^{'}} + 9 y = 0

l a pl a ce t r an s f or m cos^{2} (k t)

\int_{0}^{3} 3 d x

\frac{d}{d x} (\frac{x - ln ( 1 + x )}{x ^{2}})

\int x ln (3) d x